1. Complete the table below.

 [H+1] mol/L [OH-1] mol/L pH pOH Neutral, acidic, or basic A 1x 10-7 [ OH-] = 10 pOH = 10 7 pH=-log[H+] -log[1x 10-7] =7.0 pH + pOH =14 pOH = 14 - 7.0 = 7.0 Neutral B 1.5 x 10-3 6.7 x 10-12 2.82 11.18 Acidic C 3.0 x 10-10 3.33 x 10-5 9.52 4.48 Basic D 0.1 1 x 10-13 1.0 13.0 Acidic E [H+] = 10 pH 10 7.30 = 5.0 x 10 8 2.0 x 10-7 pH + pOH =14 pH = 14.00 -6.70 =7.30 pOH=-log[ OH-]= -log(2.0 x 10-7) = 6.70 Slightly basic F 2.5 x 10 13 4.0 x 10-2 12.6 1.4 basic G 6.3 x 10 6 1.5 x 10-9 5.20 8.80 Acidic H 2.0 x 10 -14 0.5 13.7 0.3 basic I [H+] = 10 pH =10 2.0 = 0.01 1.0 x 10 12 Stomach acid (2.0) 12.0 acidic J 1.7 x 10 7 5.9 x 10 8 Milk (6.77) 7.23 Slightly acidic K 1 x 10 12 1 x 10 2 Household cleaner (12.0) 2.0 Basic L 6.3 x 10 13 [ OH-] = 10 pOH = 10 1.80 = 1.6 x 10 2 12.20 1.80 Basic M 5.5 x 10 9 1.8 x 10 6 8.26 Baking soda (5.74) Basic N 3.2 x 10 3 3.2 x 10 12 2.5 Lemon juice (11.5) Acidic
1. Order the solutions from #2 (A to F only) from the strongest to the weakest acid. Explain which values you used and why?

D  B  A  E  C  F

Lowest pH corresponds to the strongest acid because it corresponds to the highest hydrogen ion concentration.

1. In an aqueous solution, the H+1 (aq) concentration is 2.8 x 10-4 M. What is the concentration of OH-1 (aq)?

[ OH-][H+] = 10-14

2.8 x 10-4 [ OH-] = 10-14

[ OH-] = 3.6 x 10-11 M

1. In an aqueous solution in which the OH-1 (aq) concentration is 1.0 x 10-7 M, what is the concentration of H+1 (aq)?

[ OH-][H+] = 10-14

1.0 x 10-7[H+] = 10-14

[H+] = 1.0 x 10-7 M

1. The pH of a sample of human blood was measured to be 7.41 at 25 0C. Calculate pOH, [H+1]aq, and [OH-1]aq for the sample.

[H+] =10 pH =10 7.41 = 3.9 x 10-8 mol/L

pH + pOH = 14

pOH = 14.00  7.41

pOH = 6.59

[ OH-] = 10 pOH =10 6.59 =

= 2.6 x 10-7 mol/L

6.         Identify 2 Brφnsted-Lowry bases and two acids from each of the following:

a.         HCO3- (aq)              +          NH3(aq)             CO3-2(aq)                     +          NH4+(aq)

acid(donates H+           Base                            base(in reverse rxn)                acid

to NH3)

b.         HSO4- (aq)         +          H2PO4- (aq)        H3PO4            +          SO42- (aq)

acid(donates H+           Base                            acid                             base

to H2PO4-)

7.         Show how CH3COOH can act as an acid in water.

CH3COOH      +          H2O     CH3COO-      +          H3O+