Key Concept: Series Versus Parallel Circuits

Sample Questions:

  1. (JUNE 2000 416): Examine the four electric circuits. Each consists of a power supply, two resistors, an ammeter and a voltmeter. You wish to measure the potential difference across the terminals of the power supply as well as the total current intensity of the circuit.

 

 

2. (JUNE 2000 416): Which of the following is NOT a unit of electric energy?

A. kWh

B. J

C. V

D. Ws

 

3. (JUNE 2000 416): The following electric circuit consists of a battery and three resistors (R1, R2 an R3).

 

See related notes.

4. (JUNE 2000 416): The following electric circuit consists of a power supply, two resistors and three ammeters. R1 has a resistance of 10 W and R2 = 5 W. Ammeter reads 9A.

 

What will be the current intensity readings given by A1 and A2?

A. A1 = 9 A; A2 = 9 A

B. A1 = 6 A; A2 = 3 A

C. A1 = 4.5 A; A2 = 4.5 A

D. A1 = 3 A; A2 = 6 A

  See related notes.

Not convinced? See a longer solution.

5. (JUNE 1999 416): The following electric circuit consists of a power supply, two resistors and a voltmeter, which reads 40 V.

 

What is the potential difference across the terminals of resistor R2?

A. 10 V

B. 16 V

C. 20 V

D. 40 V

  See related notes.

6. In an electric circuit the potential difference across the terminals of a resistor was set at different levels and the resulting current intensity was measured. The measurements are recorded in the table below.

Potential Difference,V, (V)

Current Intensity, I, (A)

0

0

5

1

20

4.1

35

7.1

40

8.1

 

Draw a graph using the above data and then use the graph to determine the resistance of the resistor.

No graph = no marks!

 

Answer

:

 

G=I/V= slope = (8.1-0)/(40-0) = 0.20 S but we want R=1/G=1/0.20 = 5.0 W.

 Notes:

 

Also Known as

Measured in..

Units are equivalent to

Related to ....

Voltage

Potential difference

V= volt

J/C = Joule per coulomb(charge held by large group of electrons)

Water pressure, based on how much water is in reservoir connected to your home.

Current Intensity

amperage

A = amp or ampere

C/s= coulomb per second

How much water is actually flowing out of your hose per second.

Resistance

 

W.= ohm

Js/C2

Think of a resistor as an obstacle inside your hose.

Conductance

 

S = siemen

C2/(Js)

Similar to current but also tied in to voltage

Measuring Voltage and Current.

If you look at question1, choice A, you'll see the correct way of hooking up a voltmeter, always in parallel to whatever you're measuring. Voltage is, after all, potential difference, so it has to measure the difference between the energy per coulomb before and after the electrons flow through the battery or resistor.

The ammeter, however cannot offer electrons any choice. It has to be connected in series, not parallel.

What is a Parallel Connection?

Resistors are said to be in parallel if electrons have a choice to flow through one resistor but not the other. Question #4 is an example of a parallel circuit.

What is a Series Connection?

Resistors are said to be in series if electrons have no choice but to flow through each resistor to and from the battery. Question #5 is an example of a series circuit.

Ohm's Law

V= IR applies to both series and parallel circuits. But in applying it, you have to keep the following important things in mind:

Type of circuit

Voltage

Total or equivalent resistance

Current

parallel

Is the same for all resistors connected in parallel. This happens because in parallel electrons have, on their way to different resistors, the same entry and departure point, and so have the same potential difference.

1/Re = 1/R1+1/R2...

example; in #3: 1/Re=1/3+1/18+1/6=10/18;

Re = 18/10=1.8W

Re in parallel is always smaller than any individual resistance.

It = I1 + I2 + I3;

This makes sense because although the current splits up in parallel, the electrons all meet again at some point in the circuit.

series

Vt = V1 + V2 + V3...; So a smaller resistor will experience a smaller voltage drop.

Rt = R1 + R2 + R3...

Current is