Solutions to p 14 and 15
1. Complete the following table.
Name |
Isotope Notation |
Atomic Number |
Mass Number |
Number of Protons |
Number of Neutrons |
Number of Electrons |
||||||
Neutral carbon |
C |
6 |
14 |
6 |
8 |
6 |
||||||
Neutral oxygen |
O |
8 |
15 |
8 |
7 |
8 |
||||||
Phosphide |
P-3 |
15 |
31 |
15 |
16 |
18 |
||||||
Boron |
5 |
9 |
5 |
4 |
2 |
|||||||
Selenide |
34 |
79 |
34 |
45 |
36 |
|||||||
Californium |
251Cf +2 |
98 |
251 |
98 |
153 |
96 |
||||||
Fluoride |
19F -1 |
9 |
19 |
9 |
10 |
10 |
||||||
Potassium |
K+1 |
19 |
49 |
19 |
30 |
18 |
||||||
Magnesium |
Mg+2 |
12 |
25 |
12 |
13 |
10 |
||||||
Krypton |
Kr |
36 |
77 |
36 |
41 |
36 |
||||||
Hydride |
H-1 |
1 |
3 |
1 |
2 |
2 |
||||||
Hydride |
H-1 |
1 |
2 |
1 |
1 |
2 |
||||||
Iodide |
I-1 |
53 |
127 |
53 |
74 |
54 |
||||||
Potassium |
K+1 |
19 |
40 |
19 |
21 |
18 |
||||||
Praseodymide |
Pr-1 |
59 |
140 |
59 |
81 |
60 |
||||||
Sodium |
Na+1 |
11 |
23 |
11 |
12 |
10 |
||||||
Magnesium |
Mg+2 |
12 |
24 |
12 |
12 |
10 |
||||||
Aluminum |
Al+3 |
13 |
27 |
13 |
14 |
10 |
||||||
Boron |
B+3 |
5 |
11 |
5 |
6 |
2 |
||||||
Chloride |
Cl-1 |
17 |
35 |
17 |
18 |
18 |
||||||
fluoride |
F-1 |
9 |
19 |
9 |
10 |
10 |
||||||
Calcium ion (+2) |
Ca+2 |
20 |
40 |
20 |
20 |
18 |
||||||
2. Answer the following “who am I?” questions with one of the following terms:
proton, neutron, electron, or ion.
a. I am a positively charged particle found within the nucleus______proton_______
b. I am the least heavy of the subatomic particles________electron______
c. If magnesium loses electrons, I turn into one of these____ion_____
d. Compared to carbon 13, carbon 14 has one more of these ____neutron______
e. If an atom loses one of these it becomes positively charged_____electron______
3. If it was possible to add 2 protons to a neutral neon atom (mass number : 20), what would you end up with? Show the full isotope notation of the newly created atom and all work needed to arrive at your answer.
original |
new |
Ne 10 protons 10 neutrons (=20 -10) 10 electrons( = protons since it was neutral) |
22Mg+2 ( charge = p-e) 10+2 =12 protons 10 neutrons 10 electrons |
4. Show through example how the chemical properties of an ion differ from those of its neutral counterpart.
H+ found in acid will react with skin
H2 will not react with skin