d. 3244 K – 273 = 2971 C > 2970: vibrational, rotational and translational energy.

2.

3. mass of H₂ = 40.15 – 40.00 = 0.15 kg = 150 g = 75 moles

4. Target equation: 2 FeO + 0.5 O₂ à Fe₂O₃

2FeO à 2Fe + 1 O₂ DH = + 266.5 (2) kJ

2 Fe + 1.5 O₂ à Fe₂O₃ DH = - 822.2 kJ

2 FeO + 0.5 O₂ à Fe₂O₃ DH = - 289.2 kJ

5. total volume = 200 + 300 ml = 500 ml = 500 g, since they are dilute aqueous solutions.

Q = mcDT

= 500(4.19)(35-20) = 31425 J

But this amount is released by the neutralization reaction so DH= -31.425 kJ

Moles of LiOH = 0.200L X 0.1 mol/L = 0.02 moles

DH= -31.425 kJ/0.02 moles = -1571 kJ/mole of LiOH

6. increase the temperature; powder the Mg to increase the surface area.

7. 1 mg = 0.001g = 0.001/32 = 0.00003125 moles of O₂ per second

But ratio of O₂ to FeO is 0.5 to 1 or 1 to 2, so 0.0000625moles of FeO are produced in 1 second.

In 60 sec, 60 X 0.0000625 = 0.00375 moles/minute

8. a. BHT and SO₂ are both attacked by oxygen. This molecular sacrifice spares our Bordeaux and Cheerios.

b. Chlorophyll indirectly catalyzes the breakdown of water into hydrogen ions and molecular oxygen.

CFC’s release Cl which attacks O₃ to form ClO, which in turn reacts to give back Cl.