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Solutions to 2002 Monthly Questions
The question was: In 2001 Andrew Spielman wrote a book about what he considers to be man's most persistent and deadliest foe. Whose natural history did he feature? Solution:
His book is about mosquitoes, the vectors of
(1) is transmitted by mosquitoes of the genus Anopheles. (2) and (3) are transmitted by the species Aedes aegypti. Culex pipiens, the common house mosquito, can transmit (4) and (5). Malaria was once considered to be on the verge of being conquered. But in recent decades it has made a strong comeback due to pesticide resistance, poorly administered drugs and other factors. The author still feels that DDT should not have been banned as a pesticide. If applied thoroughly and over a short time span, it still provides an effective and less toxic means of controlling the mosquito population, which spreads Plasmodium ,the organism which actually causes malaria.
The question was:
Compare the following: 4 KNO3 + 7 C +
S à K2CO3 + K2S + 3 CO + 3 CO2 +
2 N2. 10KNO3 + 16 C + 2 S à 3 K2CO3
+ 2 K2S + 5 CO + 8 CO2 + 5 N2. The equations contain identical reactants and products. Both
are balanced representations of what happens when gunpowder explodes. Yet they
are not equivalent, in the sense that one equation has not been
multiplied by a certain factor. It turns out that there are practically countless ways by which
you can balance the equation: a KNO3 + b C + c S à d K2CO3
+ e K2S + f CO + g CO2 + h N2. Mathematically, why is this so? Solution:
Each atom has to be balanced: K: a = 2d + 2e N: a = 2h O 3a = 3d + f +
2g C b = d + f + g S c = e Since c = e, then a = 2d+ 2c (see K) Dividing the equation for oxygen by 3: a = d + f/3 + 2g/3, which we can substitute in to the new
equation for K and obtain: 2d + 2c = d + f/3 + 2g/3. Solving the above for f: f = 3d + 6c –2g. Arbitrary values can then be set for c and
d, for which several values of g exist that will not render 3d + 6c – 2g a
negative value. Based on these, a, b, e and h can also be obtained.
The question was: What are we? Solution:
Cosmic rays are actually particles--mostly protons---that move almost at the speed of light and collide with molecules in our upper atmosphere. They were named by Robert Millikan, but discovered in about 1912 by the 1936 Physics Nobel Prize winner Victor Hess, who equipped high-flying balloons with electrometers. An electrometer is an instrument that measures the voltage between two electrostatically- charged bodies. Hess could not get rid of the background reading of his instrument, and, to his astonishment, he found that the reading kept increasing with altitude. The co-winner of the 1936 prize was Anderson, who discovered positrons (the positively charged electrons of anti matter) while investigating the nature of cosmic rays.
The question was:
One of the characteristic smells of barbecue smoke is caused by acrolein, an eye-irritant with the formula C3H4O. It is formed when heat breaks down glycerol, itself a breakdown product of fat.
The formula of glycerol is C3H8O3. From the formulas alone, how can you tell that glycerol does not gain or lose electrons in forming acrolein? Solution:
Since glycerol is C3H8O3, 3x + 8(+1) +3(-2) = 0, where x= C's oxidation number. x turns out to be -2/3. But for acrolein(C3H4O), 3x +4(1) +(-2) = 0, x is again -2/3. The oxidation number of carbon remains constant, so this indicates that the electrons of glycerol are just reshuffled internally under the stress of heat, the molecule decomposes, and two water molecules are expelled as glycerol turns to acrolein. What happens in the mouths of carnivores when the meat is devoured? Yes it is chewed, but are there any other chemicals in the cooked meat that make it appealing? The meaty flavour seems to be a combination of IMP ( inosine monophosphate, a breakdown product of ATP, the "energy-giving molecule" which facilitates a host of reactions in living cells) and MSG, monosodium glumate, the salt version of glutamic acid, the same substance that is used as a food additive, especially in American Chinese restaurants. Mushrooms also contain a variety of glutamic acids. For this reason, certain mushrooms (example Portobellos)that have the right combination of texture and such chemicals are very meat-like in taste. Atkins, P.W. Molecules Scientific American Library 1987
Merck Index Thirteenth Edition 1996
The question was:
Solution:
The total energy emitted by the hot plate is E = Pt = 600 (J/s)(495 s)= 29700 J.
The question was:
Dinosaurs became extinct 65 million years ago.
The present universe's entire history (assume 15 billion years) can be condensed
to 1 calendar year (non-leap year). On this calendar, on what date and at what
hour did dinosaurs become extinct? Solution:
On this calendar, dinosaurs became extinct 65 X 106y/(15 X 109y)*365 days = 1.5817 days from the tail end on Dec 31 24:00 h. 1 day ago would be Dec 31 at 12 am. 2 days ago would would be Dec 30: 12 am. To get the time, we have to move forward from Dec 30 12 am, so the time is (2-1.5817)*24h = 10 am. This of course
is assuming that we are certain of the 15 billion figure. Otherwise, the date
itself is an approximation, and the time itself, meaningless. But it does show
how recent the extinction is from the universe's point of view. 2nd June Puzzle:
The question was: This one is from an old Quirks and Quarks episode in which Crawford of McGill asks, "You have two apparently identical iron bars but only one is a bar magnet; the other is unmagnetized iron. With no other equipment, what simple experiment will help you tell them apart?"
2nd June Puzzle Solution:
Make a T-formation with the two magnets. If they stick together then the the vertical bar is the bar magnet. If they do not
attract, then the horizontal bar is the magnet because its center will have magnetic field lines that run parallel to the edge of the vertical bar and so will not attract it.
The question was:
We recently had people over for dinner, and, although
I was a good host for most of the evening, when the
conversation shifted towards the topic of cars,
I tried to calculate how much warmer a room gets from absorbing
body heat. Try to list all the relevant factors,
formulas and physical constants needed for such an estimate. Solution:
Assuming that there is no air conditioning, no open windows, and very good insulation, you would have to know: So let's try it: assume 16 people just eating and talking for 4 hours.
Each person consumes an average of 71 Calories doing so. Air has a specific heat
of 1.0 J/(g/C) and a density of 0.00129 g/cm3 = 1290 g/m3.
The adjacent rooms have a volume of 3 m X 10 m X 6 m, and an area of 60m2 Q = mcDT 71 Cal/(person*h)*4190 J/Cal * 16 people*4h - 69000J/(h m2)*(4 h)*(60m2)=
180 m3(1290 g/m3)(1.0 J/(g/C))DT DT = 10 C: very roughly. So it's not the dull conversation that
makes you sweat around the collar; it's body heat concentrated in a small space.
The question was:
Of all naturally occurring elements possessing an
even number of protons, how many have, as their most common stable isotope,
a nucleus with an odd number of neutrons? Solution:
Only 1. Beryllium. Be-9 is unique.
All other natural elements with even atomic numbers have an
even number of neutrons as their most common isotope. In the atomic nucleus there are transition states for protons
and neutrons, just like there are for electrons. Nucleons
(protons or neutrons) can move from a ground state to an excited state.
For nuclei with an even number of both protons and neutrons,
there is only one excited state for these particles,
and the gap between the two states is relatively large.
Be-9 was probably synthesized during the Big Bang but in very small amounts.
Why it's more stable then Be-8 is another mystery. Part 2 Solution
The question was
After several students spelled "noble" n-o-b-e-l on a review test, I wondered
if any discoverers of noble gases were ever awarded a Nobel prize. Has such
a thing ever happened? Solution:
William Ramsay received the 1904 Nobel Prize in chemistry for discovering Ne,Ar,Kr and Xe. Taking a hint from an experiment by
Cavendish in which he had measured a small amount of gas leftover from a reaction between nitrogen and oxygen, Ramsay finally explained why the density of nitrogen
samples obtained from air was higher than the density of nitrogen extracted from ammonia. They contained small amounts of unknown gases that behaved like helium.
The question was:
This, as they say in the movies, is based on a true story. Even with sophisticated medical technology at their fingertips, doctors can still rely on simple observations. For example,with experience and a stethoscope, they can tell a great deal about our heart and lungs. They can also look into our ears and eyes, both of which can tell a medical story. But to base a diagnosis only on the white of someone's eyes is a little extreme. There are such characters around, and one of them was visited by an old lady I know.
From peering into her gullible but otherwise good-looking eyes, he claimed to have seen a kidney condition. "Your kidneys are not too healthy", he asserted. Then he went on to prescribe some obscure oriental tea, which had to be drunk only after letting most of the water evaporate from the extract.
The woman went out and bought the product, prepared it as suggested by the character and drank it.
Two days later, after a few hours of excruciating back pains and other severe discomfort in her urinary tract, upon peeing she noticed a sandy residue at the bottom of the toilet bowl. The pain persisted for a few more hours, but she was fine the next morning.
The woman was convinced that the "prescription" had cleansed out her excretory system.
Is there another possible explanation for what she experienced?
Solution:
There is a possibility that his prescription actually caused the adverse reaction. Tea, in general, is rich in oxalates, and his recommended tea may have had an unusually high amount of the ion. Recall that the tea solution was also concentrated since water was purposely evaporated. This may have been enough to form small crystals of calcium oxalate or kidney stones within her system. What the woman experienced was definitely symptomatic of passing stones, but whether a single dose of the tea could have induced such a condition is speculation on my part.
The question was:
If a planet with half of the Earth's density weighed 32 times as much as the Earth, how much longer would it take to go around that planet? Solution:
If the planet was only half as dense then it must have had 2 X 32 = 64 times the volume. Think about it: mass / volume = density. But for the planet to be 64 times as voluminous as the earth, it only has 4 times the radius( volume is the result of the radius cubed, and the cube root of 64 is 4.) If it is four times as wide it will, have four times the circumference (since circumference is pX diameter), and it will take four times longer to go around that planet, assuming the same speed of course.
The question was:
A white dwarf is a dense stellar object.( How dense? 105 to 108 g/cm3, so it roughly has the mass of the sun crammed into something the size of the earth.) While a star shines, the pressure from its internal radiation is balanced by gravity, so our sun, for example,remains more or less the same size. But when a star "dies out" (stops fusing nuclei), it risks collapsing under its own gravity. A white dwarf, however, is supported against collapse under self-gravity by the degeneracy pressure of electrons.(The Pauli exclusion principle states that no two electrons can occupy the same quantum state.) White dwarfs, which consist mainly of carbon and oxygen ( see evolution of the elements), are formed as the evolutionary end products of stars of relatively low mass (about that of the sun); high-mass stars may end up as neutron stars or black holes. Enough already! Let's get to the question. What would happen if a white dwarf somehow collided with our sun?
Solution:
According to Michael Shara's article in the November, 2002 issue of Scientific American, a main sequence star such as our sun would be highly compressed and the ensuing pressure would cause the sun to blow itself apart in a matter of a few hours. Meanwhile,the denser white dwarf (10 million times denser) would pass through the sun relatively unscathed. Its outer layers would be warmed; there would be more nitrogen on its surface, but other than that, there would be no other sign of a collision. Luckily for our sun, such an encounter is highly unlikely.
The question was: Consider two pieces of zinc of negligible thickness sitting at the bottom of a beaker. The first piece of zinc is shaped like a flat disk with a hole in the middle. Its dimensions are revealed in the diagram below (see piece A). Ring B is smaller in diameter but thicker, as shown. 6 M HCl is added to the beaker.
Which piece of zinc will disappear faster? Why?.
They should react at exactly the same rate. Since thickness is negligible and all other factors are equal, the rate of reaction will depend only on area. But their areas are equal. Not convinced?
Copyright ©2002 Created:April/6/1996; Updated: Apr/29/2003
Solution to February 2002 Question of the
Month
Solution to March 2002 Question of the
Month
I2=I1/50log(E2/E1).
Solution to April 2002 Question of the
Month
References
Solution to May 2002 Question of the
Month
What is the liquid's specific heat?
But out of this 29700 J, only 30/210 is absorbed because that's the fraction of the area in contact
with the hot plate(the rest escapes), so Q = 29700(30/210)J = 4243 J
Q = mc DT
4243 J = 200c(70-20)
c = 4.25 J/(g C)
,probably water(experimental error accounts for small difference)
Solution to June 2002 Question of the
Month
Solution to July 2002 Question of the
Month
Solution to August 2002 Question of the
Month
This occurs because each proton pairs off with a neutron.
If the mass number is even, there is no "leftover" nucleon.
When there is an extra neutron, there are many "in between"
transition states created for that particle. This explanation,
however, cannot account for the stability of isotopes with an
odd number of protons ( like 15P-31, 11Na-23,
19K-39) which also have an unpaired neutron.
Solution to September 2002 Question of the
Month
Solution to October 2002 Question of the Month
Solution to November 2002 Question of the Month
Solution to December 2002 Question of the Month